MHT CET2017MathematicsProperties of Triangles
In Δ A B C if sin 2 A + sin 2 B = sin 2 C and l A B = 10 , then the maximum value of the area of Δ A B C is
Options
- A50
- B10 2
- C25
- D25 2
Correct answer
C. 25
Step-by-step solution
sin 2 A + sin 2 B = sin 2 C ⇒ a 2 + b 2 = c 2 (Sine Rule) ⇒ Right Angled ∆ ⇒ C = 90 o ,     B = 90 o − A Also Area A Δ A B C = 1 2 a b ..........(i) = 1 2 ( c sin A ) ( c cos A ) = 50 sin A cos A = 25 sin A ≤ 25 So maximum value of Δ A B C = 25