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MHT CET202616 April 2026Morning ShiftMathematicsQuadratic EquationActual

A ball is thrown in the air. Its height at any time t is given by h = 3 + 14t - 5t^2 , then the maximum height it can reach

Options

  1. A12.9
  2. B12.8
  3. C12.7
  4. D12.6

Correct answer

B. 12.8

Step-by-step solution

Given h = 3 + 14t - 5t^2 Differentiating with respect to t : dh dt = 14 - 10t For maximum height, dh dt = 0 : 14 - 10t = 0 t = 1.4 Substituting t = 1.4 in the equation for h : h_ max = 3 + 14(1.4) - 5(1.4)^2 h_ max = 3 + 19.6 - 5(1.96) h_ max = 22.6 - 9.8 = 12.8 Answer: 12.8

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