MHT CET202519 Apr 2025Evening ShiftMathematicsStraight LinesActual
A straight line through the origin 0 meets the line 3 y =10-4 x and 8 x+6 y+5=0 at the points A and B respectively. Then 0 divides the segment A B in the ratio.
Options
- A4: 1
- B2: 3
- C1: 5
- D1: 3
Correct answer
A. 4: 1
Step-by-step solution
Let the coordinates of point A be (x_A, y_A) and point B be (x_B, y_B) . Since A lies on 3y = 10 - 4x , or equivalently 4x + 3y - 10 = 0 , we have 4x_A + 3y_A = 10 . Similarly, B lies on 8x + 6y + 5 = 0 , yielding 8x_B + 6y_B = -5 . Since the line through O , A , and B is straight and O lies between A and B , let O divide AB internally in the ratio : 1 . By the section formula, the coordinates of O(0,0) satisfy x_A + x_B + 1 = 0 and y_A + y_B + 1 = 0 , which imply x_A = - x_B and y_A = - y_B . Substituting into the