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MHT CET202411 May 2024Morning ShiftMathematicsStraight LinesActual

Let P (-5,0), Q (0,0) and R (2,2 3 ) be three points. Then the equation of the bisector of the angle P Q R is

Options

  1. Ax- 3 2 y=0
  2. B3 2 x-y=0
  3. Cx+ 3 y=0
  4. D3 x+y=0

Correct answer

D. 3 x+y=0

Step-by-step solution

Slope of QR = 3 3 -0 3-0 = 3 i.e., =60^ Clearly, PQR =120^ OQ is the angle bisector of the angle PQR , so line OQ makes 120^ with the positive direction of X-axis. Therefore, equation of the bisector of PQR is y= 120^ x y=- 3 x 3 x+y=0

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