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MHT CET20243 May 2024Evening ShiftMathematicsStraight LinesActual

The equation of the line passing through the point of intersection of the lines 3 x-y=5 and x+3 y=1 and making equal intercepts on the axes is

Options

  1. A5 x+5 y-7=0
  2. B5 x-5 y-7=0
  3. C2 x+y-7=0
  4. Dx-y+7=0

Correct answer

A. 5 x+5 y-7=0

Step-by-step solution

Required equation passes through point of intersection of lines 3 x-y=5 and x+3 y=1 Point of intersection = ( 16 10 , -2 10 ) Equation of line in double intercept form is x a + y b =1 But a=b ...[Given] So, equation of line is x+y= a Since line passes through ( 16 10 , -2 10 ) aligned & 16 10 + -2 10 = a & 14 10 = a & a = 7 5 aligned The required equation of line is x+y= 7 5 5 x+5 y-7=0

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