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MHT CET202123 Sep 2021Evening ShiftMathematicsStraight LinesActual

The equation of line, where length of the perpendicular segment from origin to the line is 4 and the inclination of this perpendicular segment with the positive direction of X -axis is 30^ , is

Options

  1. Ax+ 3 y=8
  2. Bx- 3 y=8
  3. C3 x-y=8
  4. D3 x+y=8

Correct answer

D. 3 x+y=8

Step-by-step solution

We have ( OP )=4 and m POX =30^ P (4 30^ , 4 30^ ) (2 3 , 2) From figure, we conclude that angle made be line with +ve X axis is 120^ . Slope of line = (120^ )=- 3 Hence required equation of line L is (y-2)=(- 3 )(x-2 3 ) 3 x+y=8

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