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MHT CET202019 Oct 2020Evening ShiftMathematicsStraight LinesActual

The equation of a line passing through the point (7,-4) and perpendicular to the line passing through the points (2,3) and (1,-2) is

Options

  1. Ax+5 y+13=0
  2. Bx-5 y-13=0
  3. Cx-2 y-15=0
  4. Dx+2 y+1=0

Correct answer

A. x+5 y+13=0

Step-by-step solution

(D) Slope of line through (2,3) and (1,-2) is -2-3 1-2 =5 Hence slope of required line is - 1 5 Equation of required line is (y+4)=- 1 5 (x-7) 5 y+20=-x+7 i.e. x+5 y+13=0

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