If - 2 , 2 are cartesian co-ordinates of the point, then its polar co-ordinates are…..

Step-by-step solution

We have, r c o s θ = - 2 and r s i n θ = 2 ∴ r 2 c o s 2 θ + r 2 s i n 2 θ = 2 + 2 = 4 ⇒ r 2 c o s 2 θ + s i n 2 θ = 4 ⇒ r = ± 2 a n d θ = t a n - 1 2 - 2 θ = t a n - 1 - 1 ⇒ θ = 3 π 4 ∴ Required polar co-ordinate is r , θ = 2 , 3 π 4