MHT CET202620 April 2026Morning ShiftMathematicsThree Dimensional GeometryActual
The shortest distance between the lines x - 3 3 = y - 8 -1 = z - 3 1 and x + 3 -3 = y + 7 2 = z - 6 4 is
Options
- A5 30
- B3 30
- C2 30
- D30
Correct answer
B. 3 30
Step-by-step solution
The given lines are: L₁: x - 3 3 = y - 8 -1 = z - 3 1 L₂: x + 3 -3 = y + 7 2 = z - 6 4 The position vectors of points on the lines are a ₁ = 3 i + 8 j + 3 k and a ₂ = -3 i - 7 j + 6 k . The direction vectors of the lines are b ₁ = 3 i - j + k and b ₂ = -3 i + 2 j + 4 k . The shortest distance d between two skew lines is given by: d = |( a ₂ - a ₁) ( b ₁ b ₂)| | b ₁ b ₂| First, finding a ₂ - a ₁ : a ₂ - a ₁ = (-3 - 3) i + (-7 - 8) j + (6 - 3) k = -6 i - 15 j + 3 k Next, finding b ₁ b ₂ : b ₁ b ₂ = vmatrix i & j & k