MHT CET202619 April 2026Morning ShiftMathematicsThree Dimensional GeometryActual
The plane x 2 + y 3 + z 4 = 1 cuts the axes at the points A, B, C then the area of triangle ABC is
Options
- A29
- B41
- C61
- D51
Correct answer
C. 61
Step-by-step solution
The plane x 2 + y 3 + z 4 = 1 intersects the coordinate axes at A(2, 0, 0) , B(0, 3, 0) , and C(0, 0, 4) . The area of ABC is given by = _ xy ^2 + _ yz ^2 + _ zx ^2 , where _ xy , _ yz , and _ zx are the areas of the projections of ABC on the xy , yz , and zx planes respectively. _ xy = 1 2 2 3 = 3 _ yz = 1 2 3 4 = 6 _ zx = 1 2 4 2 = 4 = 3^2 + 6^2 + 4^2 = 9 + 36 + 16 = 61 Answer: 61