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MHT CET202613 April 2026Morning ShiftMathematicsThree Dimensional GeometryActual

The shortest distance between the lines, where the first line passes through (0,0,0) and (2,0,3) and the second line passes through (2,5,0) and (0,4,0) is

Options

  1. A24 7 units
  2. B9 7 units
  3. C1 7 units
  4. D36 7 units

Correct answer

A. 24 7 units

Step-by-step solution

The equation of the first line passing through (0,0,0) and (2,0,3) is r = a₁ + b₁ , where a₁ = 0 i + 0 j + 0 k and b₁ = 2 i + 0 j + 3 k . The equation of the second line passing through (2,5,0) and (0,4,0) is r = a₂ + b₂ , where a₂ = 0 i + 4 j + 0 k and b₂ = -2 i - j + 0 k . The shortest distance d between two lines is given by d = |( a₂ - a₁ ) ( b₁ b₂ )| | b₁ b₂ | . We have a₂ - a₁ = 4 j . Now, b₁ b₂ = vmatrix i & j & k 2 & 0 & 3 -2 & -1 & 0 vmatrix = 3 i - 6 j - 2 k . The magnitude is | b₁ b₂ | = 3^2 + (-6)^2 + (

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