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MHT CET202416 May 2024Evening ShiftMathematicsThree Dimensional GeometryActual

The equation of plane through the point (2,-1,-3): and parallel to lines x-1 3 = y+2 2 = z -4 and x 2 = y-1 -3 = z-2 2 is

Options

  1. A8 x+14 y+13 z-37=0
  2. B8 x-14 y-13 z-34=0
  3. C8 x-14 y-13 z+37=0
  4. D8 x+14 y+13 z+37=0

Correct answer

D. 8 x+14 y+13 z+37=0

Step-by-step solution

The equation of plane passing through (2,-1,-3) is a (x-2)+ b (y+1)+ c ( z +3)=0 Also, as the plane is parallel to the given two lines, aligned & 3 a+2 b-4 c=0 and 2 a-3 b+2 c=0 & a=-8, b=-14, c=-13 aligned The equation of the required plane is aligned & -8(x-2)-14(y+1)-13(z+3)=0 & 8 x+14 y+13 z+37=0 aligned

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