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MHT CET202411 May 2024Evening ShiftMathematicsThree Dimensional GeometryActual

The distance of the point (1,-5,9) from the plane x-y+z=5 measured along the line x=y=z is ______ units.

Options

  1. A3 10
  2. B10 3
  3. C10 3
  4. D20 3

Correct answer

B. 10 3

Step-by-step solution

Equation of the line can be written as x-1 1 = y+5 1 = z-9 1 = Co-ordinates of any point on the line are given as x= +1, y= -5, z = +9 Substituting in the equation of the plane, we get array ll & ( +1)-( -5)+( +9)=5 & +15=5 & =-10 & Point on the plane is (-9,-15,-1) & Required distance & = Distance between (1,-5,9) and (-9,-15,-1) & = (-9-1)^2+(-15+5)^2+(-1-9)^2 & =10 3 array

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