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MHT CET202411 May 2024Evening ShiftMathematicsThree Dimensional GeometryActual

A straight line L through the point (3,-2) is inclined at an angle of 60^ to the line 3 x+y=1 . If L also intersects the X -axis, then the equation of L is

Options

  1. Ay+ 3 x+2-3 3 =0
  2. By- 3 x+2+3 3 =0
  3. C3 y-x+3+2 3 =0
  4. D3 y+x-3+2 3 =0

Correct answer

B. y- 3 x+2+3 3 =0

Step-by-step solution

The equation of a straight line passing through (3,-2) is y+2=m(x-3) The slope of the line 3 x+y=1 is - 3 So, 60^ = m-(- 3 ) 1+m(- 3 ) 3 = m+ 3 1- 3 m On solving, we get m =0 or 3 Putting the values of m in (i), the required equation of lines are y+2=0 and y- 3 x+2+3 3 =0

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