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MHT CET202411 May 2024Morning ShiftMathematicsThree Dimensional GeometryActual

The equation of the line passing through the point (3,1,2) and perpendicular to the lines x-1 1 = y-2 2 = z-3 3 and x -3 = y 2 = z 5 is

Options

  1. Ax+3 2 = y+1 7 = z+2 4
  2. Bx-3 -2 = y-1 7 = z-2 4
  3. Cx-3 2 = y-1 -7 = z-2 4
  4. Dx-3 2 = y-1 5 = z-2 4

Correct answer

C. x-3 2 = y-1 -7 = z-2 4

Step-by-step solution

Required line is perpendicular to the lines x-1 1 = y-2 2 = z-3 3 and x -3 = y 2 = z 5 . Required line is parallel to vector b = | array ccc i & j & k 1 & 2 & 3 -3 & 2 & 5 array |=4 i -14 j +8 k The equation of the required line is x-3 2 = y-1 -7 = z-2 4

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