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MHT CET202410 May 2024Morning ShiftMathematicsThree Dimensional GeometryActual

Equation of the plane, through the points (-1,2,-2) and (-1,3,2) and perpendicular to y z - plane, is

Options

  1. A4 y+z=10
  2. B4 y-z+10=0
  3. C4 y-z=10
  4. D4 y+z+10=0

Correct answer

C. 4 y-z=10

Step-by-step solution

Equation of plane passing though (-1,2,-2) and (-1,3,2) is x+1 (-1+1) = y-3 2-3 = z-2 -2-2 Above plane is perpendicular to y z - plane aligned & y-3 -1 = z-2 -4 & 4(y-3)=z-2 & 4 y-12-z+2=0 & 4 y-z=10 aligned

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