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MHT CET20244 May 2024Evening ShiftMathematicsThree Dimensional GeometryActual

If the points (1,-1, ) and (-3,0,1) are equidistant from the plane 3 x-4 y-12 z+13=0 , then the sum of all possible values of is

Options

  1. A7 3
  2. B10 3
  3. C4 3
  4. D5 3

Correct answer

B. 10 3

Step-by-step solution

Since the points (1,-1, ) and (-3,0,1) are equidistant from the given plane aligned & | 3+4-12 +13 9+16+144 |= | -9-12+13 9+16+144 | & |3+4-12 +13|=|-9-12+13| & 20-12 = 8 aligned =1, 7 3 Sum of all possible values of =1+ 7 3 = 10 3

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