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MHT CET20243 May 2024Morning ShiftMathematicsThree Dimensional GeometryActual

Equation of the plane containing the straight line x 3 = y 2 = z 4 and perpendicular to the plane containing the straight lines x 4 = y 3 = z 2 and x 2 = y -4 = z 3 is

Options

  1. A6 x-67 y-29 z =0
  2. B6 x+67 y-29 z=0
  3. C6 x-67 y+29 z=0
  4. D6 x+67 y+29 z=0

Correct answer

C. 6 x-67 y+29 z=0

Step-by-step solution

Equation of the plane containing x 4 = y 3 = z 2 and x 2 = y -4 = z 3 is aligned & | array ccc x & y & z 4 & 3 & 2 2 & -4 & 3 array |=0 & 17 x-8 y-22 z=0 aligned Now required plane is perpendicular to this plane. Consider option (C) (17)(6)+(-8)(-67)+(-22)(29)=0 Option (C) is correct.

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