MHT CET20242 May 2024Evening ShiftMathematicsThree Dimensional GeometryActual
Let P be the image of the point (3,1,7) with respect to the plane x-y+z=3 . Then the equation of the plane passing through P and containing the straight line x 1 = y 2 = z 1 is
Options
- A-4 y-x+7 z =0
- Bx-4 y-7 z=0
- Cx-4 y+7 z=0
- Dx+4 y+7 z=0
Correct answer
C. x-4 y+7 z=0
Step-by-step solution
The d.r.s. of the normal to the plane are 1,-1,1 The equation of line QM is aligned & x-3 1 = y-1 -1 = z-7 1 = ( say ) & x= +3, y=- +1, z= +7 aligned Let M ( +3,- +1, +7) Equation of plane becomes aligned & 1( +3)-1(- +1)+1( +7)=3 & 3 +6=0 =-2 & M (1,3,5) aligned Since M is the midpoint of PQ . 3+ a 2 =1, 1+ b 2 =3, 7+ c 2 =5 a=-1, b=5, c=3 Equation of the plane passing through P and containing the given line is aligned & | array ccc x+1 & y-5 & z-3 1 & -5 & -3 1 & 2 & 1 array |=0 & x-4 y+7 z=0 aligned