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MHT CET20242 May 2024Morning ShiftMathematicsThree Dimensional GeometryActual

The equation of the line passing through the point (-1,3,-2) and perpendicular to each of the lines x 1 = y 2 = z 3 and x+2 -3 = y-1 2 = z+1 5 , is

Options

  1. Ax+1 2 = y-3 7 = z+2 4
  2. Bx+1 -2 = y-3 -7 = z+2 4
  3. Cx+1 2 = y-3 7 = z+2 -4
  4. Dx+1 2 = y-3 -7 = z+2 4

Correct answer

D. x+1 2 = y-3 -7 = z+2 4

Step-by-step solution

Let a , b , c be the direction ratios of the required line. Since the line is perpendicular to the lines with d.r.s. 1, 2, 3 and -3,2,5 . array ll & a+2 b+3 c=0 & and -3 a+2 b+5 c=0 & a 2 = b -7 = c 4 array ...[From (i) and (ii)] Equation of the required line is x+1 2 = y-3 -7 = z+2 4

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