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MHT CET202314 May 2023Morning ShiftMathematicsThree Dimensional GeometryActual

Equation of the plane passing through (1,-1,2) and perpendicular to the planes x+2 y-2 z=4 and 3 x+2 y+z=6 is

Options

  1. A6 x-7 y-4 z-5=0
  2. B6 x+7 y-4 z+5=0
  3. C6 x-7 y+4 z+5=0
  4. D6 x+7 y+4 z-5=0

Correct answer

A. 6 x-7 y-4 z-5=0

Step-by-step solution

The equation of plane passing through (1,-1,2) is a (x-1)+ b (y+1)+ c ( z -2)=0 Since plane (i) is perpendicular to the planes x+2 y-2 z=4 and 3 x+2 y+z=6 array ll & a+2 b-2 c=0 & and 3 a+2 b+c=0 & a 6 = b -7 = c -4 array The equation of the required plane is aligned & 6(x-1)-7(y+1)-4(z-2)=0 & 6 x-7 y-4 z-5=0 aligned

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