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MHT CET202312 May 2023Evening ShiftMathematicsThree Dimensional GeometryActual

Equation of plane containing the line x 2 = y 3 = z 4 and perpendicular to the plane containing the lines x 3 = y 4 = z 2 and x 4 = y 2 = z 3 is

Options

  1. Ax+2 y+z=0
  2. Bx+2 y-z=0
  3. Cx-2 y+z=0
  4. Dx-2 y- z =0

Correct answer

C. x-2 y+z=0

Step-by-step solution

Equation of the plane containing x 3 = y 4 = z 2 and x 4 = y 2 = z 3 is aligned & | array ccc x & y & z 3 & 4 & 2 4 & 2 & 3 array |=0 & 8 x-y-10 z=0 aligned Now required plane is perpendicular to this plane. Consider option (C) (8)(1)+(-1)(-2)+(-10)(1)=0

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