MHT CET202312 May 2023Morning ShiftMathematicsThree Dimensional GeometryActual
The equation of the plane through (-1,1,2) whose normal makes equal acute angles with co-ordinate axes is
Options
- Ax+y+z-3=0
- Bx+y+z-2=0
- Cx+y-z-2=0
- Dx-y+z-3=0
Correct answer
B. x+y+z-2=0
Step-by-step solution
Note that (-1,1,2) is satisfied by only option (B) Alternate Method: Let A (-1,1,2) aligned a & =- i + j +2 k & n = i + j + k aligned equation of plane is r n = a n aligned & r ( i + j + k )=(- i + j +2 k ) ( i + j + k ) & r ( i + j + k )=2 & (x i +y j + z k ) ( i + j + k )=2 & x+y+ z -2=0 aligned