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MHT CET202311 May 2023Evening ShiftMathematicsThree Dimensional GeometryActual

The equation of line passing through the point (1,2,3) and perpendicular to the lines x-2 3 = y-1 2 = z+1 -2 and x 2 = y -3 = z 1 is

Options

  1. Ar =( i +2 j +3 k )+ (4 i +7 j -13 k )
  2. Br =( i +2 j +3 k )+ (-4 i +7 j -13 k )
  3. Cr =( i +2 j +3 k )+ (-4 i -7 j -13 k )
  4. Dr =( i +2 j +3 k )+ (4 i -7 j -13 k )

Correct answer

C. r =( i +2 j +3 k )+ (-4 i -7 j -13 k )

Step-by-step solution

Required line is perpendicular to the lines x-2 3 = y-1 2 = z+1 -2 and x 2 = y -3 = z 1 Required line is parallel to vector b = | array ccc i & j & k 3 & 2 & -2 2 & -3 & 1 array |=-4 i -7 j -13 k The equation of the required line is ( i +2 j +3 k )+ (-4 i -7 j -13 k )

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