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MHT CET202211 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual

The equation of a line passing through the point (2,1,3) and perpendicular to the lines x-1 1 = y-2 2 = z-3 3 and x -3 = y 2 = z 5 is

Options

  1. Ax-2 -2 = y-1 7 = z-3 4
  2. Bx-2 2 = 1-y 7 = z-3 4
  3. Cx-2 2 = y-1 4 = z-3 7
  4. Dx-2 2 = 1-y 4 = z-3 7

Correct answer

B. x-2 2 = 1-y 7 = z-3 4

Step-by-step solution

d.r's of perpendicular to both the given lines can be obtained by aligned & a 2 5-2 3 = b -3 3-1 5 = c 1 2-(-3) 2 & a 4 = b -14 = c 8 & d.r's are aligned now, required equation of the line x-2 2 = y-1 -7 = z-3 4 x-2 2 = 1-y 7 = z-3 4

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