MHT CET202211 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual
The line drawn (4,-1,2) and (-3,2,3) meets the plane at right angles at the point (-10,5,4) then the equation of plane is
Options
- A2 x-y-z+29=0
- B7 x-3 y-z+89=0
- Cx-y+z+11=0
- Dx+y+z+1=0
Correct answer
B. 7 x-3 y-z+89=0
Step-by-step solution
d.r's of normal to the plane are ^0 and it passes through (-10,5,4) . Hence the required equation is aligned & 7(x-(-10))-3(y-5)-1(z-4)=0 & 7 x-3 y-z+89=0 aligned