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MHT CET202210 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual

If the foot of the perpendicular drawn from the origin to a plane is M(-1,-2,2) , then the vector equation of the plane is

Options

  1. Ar (- i -2 j +2 k )=9
  2. Br ( i +2 j +2 k )=9
  3. Cr (- i -2 j -2 k )=9
  4. Dr ( i +2 j -2 k )=9

Correct answer

A. r (- i -2 j +2 k )=9

Step-by-step solution

D.r's of normal to the plane D.c's of Normal to the plane length of perpendicular = 1^2+2^2+(-2)^2 =3 Hence, Equation of plane r (- 1 3 i - 2 3 j + 2 3 k )=3 r (- i -2 j +2 k )=9

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