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MHT CET20228 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual

The Cartesian equation of a line is x+2 3 = y-4 2 = z-5 5 , then the vector equation of the line is

Options

  1. Ar =(-2 i +4 j +5 k )+ (3 i +2 j +5 k )
  2. Br =(2 i -4 j -5 k )+ (-3 i +2 j -5 k )
  3. Cr =(-2 i +4 j +5 k )+ (10 i +25 j -16 k )
  4. Dr =(3 i +2 j +5 k )+ (10 i +25 j -16 k )

Correct answer

B. r =(2 i -4 j -5 k )+ (-3 i +2 j -5 k )

Step-by-step solution

The line x+2 3 = y-4 2 = z-5 5 is passing through (-2,4,5) and has d.r's Hence, the vector equation is r =(-2 i +4 j +5 k )+ (3 i +2 j +5 k )

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