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MHT CET20227 Aug 2022Evening ShiftMathematicsThree Dimensional GeometryActual

The vector equation of plane containing the pint (1,-1,2) and perpendicular to planes 2 x+3 y-2 z=5 and x+2 y-3 z=8 is

Options

  1. Ar (-5 i +4 j + k )=7
  2. Br (-5 i +4 j - k )=-7
  3. Cr (-5 i +4 j + k )=-7
  4. Dr (-5 i +4 j - k )=7

Correct answer

C. r (-5 i +4 j + k )=-7

Step-by-step solution

D.R's of the required plane can be obtained by aligned & a 3 (-3)-2 (-2) = b 1 (-2)-2 (-3) = c 2 2-1 3 & a -5 = b 4 = c 1 aligned the required equation is aligned & -5(x-1)+4(y+1)+1(z-2)=0 & -5 x+4 y+z=-7 & r (-5 i +4 j + k )=-7 aligned

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