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MHT CET20227 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual

If the position vectors of the point A and B are 3 i + j +2 k and i -2 j -4 k respectively, then the equation of the plane through B and perpendicular to AB is

Options

  1. A2 x+3 y+6 z+9=0
  2. B2 x+3 y+6 z-11=0
  3. C2 x+3 y+6 z+28=0
  4. D2 x-3 y-6 z-32=0

Correct answer

C. 2 x+3 y+6 z+28=0

Step-by-step solution

The normal to the plane is along AB aligned & =-( i -2 j -4 k )-(3 i + j +2 k ) & =-2 i -3 j -6 k aligned Hence, d.r.s of normal to the plane are so equation of the plane 2 x+3 y+6 z+ =0 but it passes through (1,-2,-4) , so =28 2 x+3 y+6 z+28=0

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