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MHT CET20225 Aug 2022Morning ShiftMathematicsThree Dimensional GeometryActual

The equation of the line passing through the point (-1,3,-2) and perpendicular to each of the lines x 1 = y 2 = z 3 and x+2 -3 = y-1 2 = z+1 5 is

Options

  1. Ax+1 2 = y-3 7 = z+2 4
  2. Bx+1 2 = y+3 -7 = z+2 4
  3. Cx-1 2 = y+3 7 = z-2 4
  4. Dx-1 2 = y+3 -7 = z-2 4

Correct answer

B. x+1 2 = y+3 -7 = z+2 4

Step-by-step solution

The direction ratios of the required line can be obtained by aligned & a 2 5-2 3 = b -3 3-1 5 = c 1 2-(-3) 2 & a , b , c 4,-14,8 2,-7,4 aligned Hence, the equation of required line aligned & x-(-1) 2 = y-3 -7 = z-(-2) 4 & x+1 2 = y-3 -7 = z+2 4 aligned

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