MHT CET202124 Sep 2021Evening ShiftMathematicsThree Dimensional GeometryActual
The co-ordinates of the points on the line x+2 1 = y-1 2 = z+1 -2 at a distance of 12 units from the point A (-2,1,-1) are
Options
- A(2,9,-9),(-6,-7,7)
- B(2,9,7),(6,5,-9)
- C(6,9,-5),(-10,9,-5)
- D(6,-7,3),(-10,9,3)
Correct answer
A. (2,9,-9),(-6,-7,7)
Step-by-step solution
x +2 1 = y -1 2 = z +1 -2 = (say) Hence coordinates of any point on the given line are ( -2,2 +1,-2 -1) . This point is at a distance of 12 units from (-2,1,-1) . array ll & 12= ( -2+2)^2+(2 +1-1)^2+(-2 -1+1)^2 & = ^2+4 ^2+4 ^2 =3 & = 4 Required point =(2,9,-9) or (-6,-7,7) array