MHT CET202020 Oct 2020Evening ShiftMathematicsThree Dimensional GeometryActual
The equation of a plane containing the line x-2= y-4 4 = z-6 7 and parallel to the line r =( i +3 +5 k )+ (3 +5 +7 k ) is
Options
- Ax-2 y+z=10
- B3 x-2 y+z=4
- Cx-2 y+z=9
- Dx-2 y+z=0
Correct answer
D. x-2 y+z=0
Step-by-step solution
d.r. of given liens are (1,4,7) and (3,5,7) . Normal to the plane is perpendicular to them. array l = | array ccc i & j & k 1 & 4 & 7 3 & 5 & 7 array | = i (-7)- j (-14)+ k (-7) =-7( i -2 j + k ) array Hence eq. of plane is -7(x-2 y+z)=a This plane plasses through point (2,4,6) a=-7(2-8+6)=0 Eq. of plane is x-2 y+z=0