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MHT CET202020 Oct 2020Evening ShiftMathematicsThree Dimensional GeometryActual

The position vector of the point of intersection of the line r =(2 + -4 k )+ ( -2 +2 k ) and XOY-Plane is

Options

  1. A4 +3 k
  2. B4 +3
  3. C4 -3 k
  4. D4 -3

Correct answer

D. 4 -3

Step-by-step solution

We have line r =(2 i + j -4 k )+ ( i -2 j +2 k ) Hence coordinates of any point on this line are ( +2,-2 +1,2 -4) This point lies on XOY plane whose equation is z=0 2 -4=0 =2 Hence point of intersection is (4,-3,0) . Thus pv is 4 i -3 j

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