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MHT CET202019 Oct 2020Evening ShiftMathematicsThree Dimensional GeometryActual

The equations of planes parallel to the plane x+2 y+2 z+8=0 , which are at a distance of 2 units from the point (1,1,2) are

Options

  1. Ax+2 y+2 z-13=0 or x+2 y+2 z-1=0
  2. Bx+2 y+2 z-6=0 or x+2 y+2 z-7=0
  3. Cx+2 y+2 z+3=0 or x+2 y+2 z-5=0
  4. Dx+2 y+2 z-5=0 or x+2 y+2 z-3=0

Correct answer

A. x+2 y+2 z-13=0 or x+2 y+2 z-1=0

Step-by-step solution

(B) The equation of the plane parallel to the plane x+2 y+2 z+18=0 is x+2 y+2 z+ =0 . Now, the distance of this plane from the print (1,1,2) is | 1(1)+2(1)+2(2)+ 1²+2²+2² |= | 7+ 3 | array l We have | 7+ 3 |=2 7+ 3 = 2 = 6-7=1 =-1 or =-13 array Hence, equations of plane are x+2 y+2 z-1=0 or x+2 y+2 z-13=0

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