The shortest distance between the lines 1+x=2 y=-12 z and x=y+2=6 z-6 is

Step-by-step solution

Shortest distance between the lines array c x+1 1 = y ( 1 2 ) = z ( -1 12 ) and x 1 = y+2 1 = z-1 ( 1 6 ) is array c 0+1-2-0 1 1 2 & -1 12 1 & 1 6 array d= ( 1 6 + 1 12 )²+ (1- 1 2 )²+ ( 1 12 + 1 12 )² 12 array = | array ccc 1 & -2 & 1 1 & 1 2 & -1 12 1 & 1 & 1 6 array | ( 1 4 )²+ ( 1 2 )²+ ( 1 6 )² = (1) ( 1 12 + 1 12 )+2 ( 1 6 + 1 12 )+ (1- 1 2 ) 1 16 + 1 4 + 1 36 = | 1 6 + 1 2 + 1 2 | 9+36+4 144 = | 7 6 | 49 144 = 7 6 12 7 =2