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MHT CET202013 Oct 2020Evening ShiftMathematicsThree Dimensional GeometryActual

The equation of a line passing through the point (2,4,6) and parallel to the line 3 x+4=4 y-1=1-4 z is

Options

  1. Ax-2 4 = y-4 3 = z-6 3
  2. Bx-2 4 = y-4 3 = z-6 -3
  3. Cx-2 -4 = y-4 3 = z-6 -3
  4. Dx-2 -4 = y-4 -3 = z-6 -3

Correct answer

B. x-2 4 = y-4 3 = z-6 -3

Step-by-step solution

Given equation of line is 3 x+4 x+ 4 3 = y- 1 4 ( 1 3 ) = z- 1 4 ( 1 4 ) = 3 (x+ 4 3 ) (- 1 4 ) = 4 (y- 1 4 ) 1 = -4 (z- 1 4 ) 1 aligned & x+ 4 3 ( 1 3 ) = y- 1 4 ( 1 4 ) = z- 1 4 (- 1 4 ) & 1 3 , 1 4 ,- 1 4 are d.r. of a line i.e. 4,3,-3 aligned Hence eq. of required line is x-2 4 = y-4 3 = z-6 -3

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