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MHT CET202013 Oct 2020Morning ShiftMathematicsThree Dimensional GeometryActual

The equation of the line passing through the point (2,3,-4) and perpendicular to XOZ plane is

Options

  1. Ax=-2 ; y=3+ ; z=4
  2. Bx-2 1 = z+4 1 ; y=3
  3. Cx=-2 ; y=-3+ ; z=4
  4. Dx=2 ; y=3+ ; z=-4

Correct answer

D. x=2 ; y=3+ ; z=-4

Step-by-step solution

Direction cosines of normal are , , are 90^ , 0^ , 90^ i.e. 0,1,0 The line is parallel to normal of the plane. Required line is x-2 0 = y-3 1 = z+4 0 = ( say ) x=2 ; y=3+ ; z=-4

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