MHT CET202012 Oct 2020Morning ShiftMathematicsThree Dimensional GeometryActual
The equation of a plane containing the point (1,-1,1) and parallel to the plane 2 x+3 y-4 z=17 is
Options
- Ar _ (2 +3 -4 k )=-5
- Br (2 +3 -4 k )=-15
- Cr (4 +3 -4 k )=-3
- Dr (3 +4 -2 k )=-3
Correct answer
A. r _ (2 +3 -4 k )=-5
Step-by-step solution
Equation of plane passing through the point having position vector a and normal to n is r n (2 i +3 j -4 k )=( i - j + k ) (2 i +3 j -4 k )=2-3-4=-5