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MHT CET202012 Oct 2020Morning ShiftMathematicsThree Dimensional GeometryActual

If cartesian equation of the line is x-1=2 y+3=3-z , then its vector equation is

Options

  1. Ar =( -3 +3 k )+ (2 + -2)
  2. Br =(- -3 +3 k )+ ( + 1 2 - k )
  3. Cr = (- + 3 2 -3 k )+ (2 + -2 k )
  4. Dr = ( - 3 2 +3 k )+ (2 + -2 k )

Correct answer

D. r = ( - 3 2 +3 k )+ (2 + -2 k )

Step-by-step solution

Given Cartesian equation is aligned x-1 &=2 y+3=3-z x-1 1 &= 2 (y+ 3 2 ) 1 = -(z-3) 1 x-1 1 = y+ 3 2 ( 1 2 ) = z-3 -1 aligned array l 1, 1 2 ,-1 i.e. 2,1,-2 are d.r. of given line. A (1,- 3 2 , 3 ) lies on given line. vector equation is r = a + b = ( i - 3 2 j +3 k )+ (2 i + j -2 k ) array

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