MHT CET2019Evening ShiftMathematicsThree Dimensional GeometryActual
Equations of planes parallel to the plane x - 2 y + 2 z + 4 = 0 which are at a distance of one unit from the point 1,2 , 3 are …..
Options
- Ax + 2 y + 2 z = - 6 , x + 2 y + 2 z = 5
- Bx - 2 y - 6 = 0 , x - 2 y + z = 6
- Cx - 2 y + 2 z = 6 , x + 2 y + 2 z = 0
- Dx - 2 y + 2 z = 0 , x - 2 y + 2 z - 6 = 0
Correct answer
D. x - 2 y + 2 z = 0 , x - 2 y + 2 z - 6 = 0
Step-by-step solution
Given equation of plane x - 2 y + 2 z + 4 = 0 ….(i) Equation of plane parallel (ii) from point (1, 2, 3) is 1 unit ∴ 1 1 - 2 2 + 2 3 + k 1 2 + - 2 2 + 2 2 = 1 ⇒ 1 - 4 + 6 + k 1 + 4 + 4 = 1 ⇒ 3 + k 9 = 1 ⇒ 3 + k = 3 ⇒ 3 + k = ± 3 ∴ x - 2 y + 2 z + 0 = 0 and x - 2 y + 2 z - 6 = 0 ⇒ x - 2 y + 2 z = 0 and x - 2 y + 2 z - 6 = 0