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MHT CET2017MathematicsThree Dimensional Geometry

The lines x - 1 2 = y + 1 2 = z - 1 4 and x - 3 1 = y - 6 2 = z 1 intersect each other at point

Options

  1. A - 2 , - 4 , 5
  2. B- 2 , - 4 , - 5
  3. C2 , 4 , - 5
  4. D2 , - 4 , - 5

Correct answer

B. - 2 , - 4 , - 5

Step-by-step solution

A General point on L 1 is x - 1 2 = y + 1 2 = z - 1 4 = r ⇒ P r = 1 + 2 r , - 1 + 2 r , 1 + 4 r Substituting the coordinates of this point in the equation of L 2 1 + 2 r - 3 1 = - 1 + 2 r 2 = 1 + 4 r 1 ⇒ 2 r - 2 = 4 r + 1 ⇒ r = - 3 2 So the intersection point is (-2, -4, -5)

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