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MHT CET2010MathematicsThree Dimensional Geometry

The equation of the plane which passes through (2,-3,1) and is normal to the line joining the points (3,4,-1) and (2,-1,5) , is given by

Options

  1. Ax+5 y-6 z+19=0
  2. Bx-5 y+6 z-19=0
  3. Cx+5 y+6 z+19=0
  4. Dx-5 y-6 z-19=0

Correct answer

A. x+5 y-6 z+19=0

Step-by-step solution

The equation of plane is array lr (x-2)+5(y+3)-6(z-1)=0 x+5 y-6 z+19=0 array

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