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MHT CET2010MathematicsThree Dimensional Geometry

The point where the line x-1 2 = y-2 -3 = z+3 4 meets the plane 2 x+4 y-z=1 , is

Options

  1. A(3,-1,1)
  2. B(3,1,1)
  3. C(1,1,3)
  4. D(1,3,1)

Correct answer

A. (3,-1,1)

Step-by-step solution

Let point be (a, b, c) , then 2 a+4 b-c=1 (i) and a=2 k+1, b=-3 k+2 and c=4 k-3 (where k is constant) On substituting these values in Eq. (i), we get 2(2 k+1)+4(-3 k+2)-(4 k-3)=1 =1 Hence, required point is (3,-1,1) .

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