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MHT CET2008MathematicsThree Dimensional Geometry

The equation of the plane containing the line x+1 -3 = y-3 2 = z+2 1 and the point (0,7,-7) is

Options

  1. Ax+y+z=1
  2. Bx+y+z=2
  3. Cx+y+z=0
  4. DNone of these

Correct answer

C. x+y+z=0

Step-by-step solution

The equation of plane containing the line x+1 -3 = y-3 2 = z+2 1 is a(x+1)+b(y-3)+c(z+2)=0 ...(i) where -3 a+2 b+c=0 ...(ii) This passes through (0,7,-7) . +4 b-5 c=0 ...(iii) From Eqs. (ii) and (iii), or aligned a -14 &= b -14 = c -14 a 1 &= b 1 = c 1 aligned Thus, the required plane is x+y+z=0

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