MHT CET202123 Sep 2021Evening ShiftMathematicsTrigonometric EquationsActual
If 3 =2 3 and 0 < < , then =
Options
- A2 5
- B3 2 2
- C2 3
- D3 5
Correct answer
B. 3 2 2
Step-by-step solution
aligned & 3 =2 3 & =2 (3 -4 ^2 ) & 8 ^3 -3 =0 & (8 ^2 -3 )=0 & =0 or = 3 8 = 3 2 2 aligned Since, 0 < < , we write = 3 2 2