If (x+y)+ (x+y)= [ ⁻¹ ( 1 3 ) ] , then d y d x =

Step-by-step solution

(D) Let ⁻¹ ( 1 3 )= = 1 3 = 1- 1 9 = 2 2 3 (x+y)+ (x+y)= [ ⁻¹ ( 2 2 3 ) ] (x+y)+ (x+y)= 2 2 3 Differentiating both sides. w.r.t. x array l (x+y) (1+ d y d x )-s x+y= ⁻¹(1)= 4 array Differentiating w.r.t. x , we get 1+ d y d x =0 d y d x =-1