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MHT CET20192 May 2019Morning ShiftMathematicsTrigonometric EquationsActual

The number of solutions of sin 2 ⁡ θ = 1 2 in 0 , π is ________

Options

  1. Athree
  2. Bfour
  3. Ctwo
  4. Done

Correct answer

C. two

Step-by-step solution

Given: Equation s i n 2 θ = 1 2 θ ∈ 0 , π s i n θ = ± 1 2 but θ ∈ 0 , π Then, θ = π 4 , 3 π 4

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