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MHT CET202615 April 2026Morning ShiftMathematicsTrigonometric Ratios & IdentitiesActual

If P = 20^ , then the value of 160^ - 110^ 1 + 160^ 110^ in terms of P , is...

Options

  1. A1+P^2 2P^2
  2. B1+P^2 2P
  3. C1-P^2 2P^2
  4. D1-P^2 2P

Correct answer

D. 1-P^2 2P

Step-by-step solution

We have P = 20^ . Expressing the terms in the given expression using 20^ : 160^ = (180^ - 20^ ) = - 20^ = -P 110^ = (90^ + 20^ ) = - 20^ = - 1 20^ = - 1 P Substituting these values into the given expression: 160^ - 110^ 1 + 160^ 110^ = -P - (- 1 P ) 1 + (-P) (- 1 P ) = 1 P - P 1 + 1 = 1 - P^2 P 2 = 1 - P^2 2P Answer: 1-P^2 2P

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