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AP EAMCET2006MathematicsBasics of Mathematics

12- 68+48 2 is equal to :

Options

  1. A2 -3
  2. B2+ 2
  3. C2- 2
  4. D6-2 8

Correct answer

C. 2- 2

Step-by-step solution

12- 68+48 2 = 12- (6)^2+(4 2 )^2+2 6 4 2 = 12- (6+4 2 )^2 = 12-6-4 2 = 6-4 2 = (2)^2+( 2 )^2-2 2 2 = (2- 2 )^2 =2- 2

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